3x^2+15x=32

Solution for 3x^2+15x=32 equation:

3x^2+15x=32

We move all terms to the left:

3x^2+15x-(32)=0

a = 3; b = 15; c = -32;
Δ = b2-4ac
Δ = 152-4·3·(-32)
Δ = 609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{609}}{2*3}=\frac{-15-\sqrt{609}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{609}}{2*3}=\frac{-15+\sqrt{609}}{6}
$